/* This program inputs a list of positive numbers (we assume between 1 and 99) from the user to store in an array.
 * It then iterates from 1 to 99 and for each number, iterates through the array to count the number of times that
 * number (e.g., 1) appears in the array.  If the number appears any number of times, the program outputs the 
 * number and how many times it appears. */

import java.util.Scanner;

public class Prog7_3
{
	public static void main(String[] args)
	{
		int[] values = new int[100];				// assume a list of no more than 100 elements
		int number = 0;								// number of elements currently in the array
		int temp;									// to store the input value temporarily
		Scanner in = new Scanner(System.in);
		System.out.print("Enter a list of values, one at a time, ending with 0  ");
		temp = in.nextInt();
		while(temp>0&&number<100)					// iterate while the input is legal and we have room in the array
		{
			values[number++] = temp;				// add the latest input to the array and get the next input
			System.out.print("Enter the next value, 0 to exit  ");
			temp = in.nextInt();
		}
		int count;									// to count how many times a given number appears in the array
		for(int i=1;i<=99;i++)
		{
			count=0;								// (re)set count to 0 before we start counting the next value
			for(int j=0;j<number;j++)				// for each number in the array
				if(values[j]==i) count++;			// if the array element matches the value we are looking for (i), count it
			if(count>0) System.out.println("The value " + i + " appears " + count + " times");	// if we found any i's in the array, output how many
		}
	}
}